Final position of block " = 0.63 m

pellet

initial position of block
pellet of mass 8.80 g strikes a stationary wooden block and is completely embedded in
t. The centre of mass of the block rises by 0.63 m. The wooden block has a mass of 450
(a)
Determine the speed of the pellet when it strikes the wooden block.

(b) The wooden block is replaced by a steel block of the same mass. The experiment is
repeated with the steel block and an identical pellet. The pellet rebounds after striking the
block. Discuss how the height the steel
with the height of 0.63 m
reached by the wooden block. In your an
ergy and momentum changes
that occur in the two experiments.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

we need to know the time interval during which the force acts. impulse of force = momentum change