The resistivity of copper is 1.77×10-11 Ωm. A copper wire of length 56.5 cm and cross-sectional area 1×10-6m2 is connected to the two sides of a 9 V battery. If no other resistance is connected to the battery, what will be the current flowing in the wire? 9.0×105 A

1.0×105 A

2.9×105 A

1.1×105 A

Current I is 9 × 10^-5

Explanation:

Data :

resistivity = p = 1.77 × 10^-11 ohm m

Lenght = L = 56.5 cm = 0.565 m

Area = A = 1 ×10^-6 m²

Potential difference = V = 9v

Formula for resistivity

 p = (RA)/ L

Put values

R = (p L)/A

R = 1 × 10^-5

Formula to find current I

V = IR   or I = V/R

Put values

I = 9 /1 × 10^-5

    I = 9 × 10 ^-5 A

where are the vectors ?

conduction, convection, radiation