A 80.0 g egg dropped from a window is caught by a student. If the student exerts a net force of −2.5 N over a period of 0.25 s to bring the egg to a stop, what is the egg’s initial speed?

Known :

m = 80 gr = 0.08 kg

F = 2.5 N

∆t = 0.25 s

Solution :

F . ∆t = ∆P

F . ∆t = m(v₂ - v₁)

(-2.5 N)(0.25 s) = (0.08 kg)(0 - v₁)

v₁ = 7.8125 m/s

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explanation: