PLEASE HELP THIS IS DUE IN 24 HOURS Starting from rest, a(n)10 kg block slides 11.9 m down a frictionless ramp (inclined at
30◦ from the floor) to the bottom. The block then slides an additional 21.1 m along the floor before coming to stop. The acceleration of gravity is 9.8 m/s2.

A) Find the speed of the block at the bottom of the ramp.

B)Find the coefficient of kinetic friction between block and floor

C)Find the magnitude of the mechanical energy lost due to friction.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

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hope this !