Now find what k value would be needed to stretch the spring 0.25 m at a force value of 25 N.

Hi there!

Using Hooke's Law:

F = force (N)

k = Spring Constant (N/m)

x = displacement from equilibrium (m)

Plug in the given values:

25 = k(0.25)

25 = 0.25k

Solve for k:

25/0.25 = k

k = 100 N/m

im sorry i dont know

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