A marble with a mass of 1. 5 grams rolls at a constant rate of 0. 50 cm/s across a table. What is the magnitude of the marble's momentum?.

Explanation:

The momentum can be calculated as follows:

p = mv

Where m is the mass of the marble and v its velocity. Therefore:

p = 0.0015kg · 0.0005m/s = 0.0000075 kg·m/s = 7,5·10^{-6}kg·m/s

Note that we have converted the grams in kg and cm/s in m/s.

7.5 × 10⁻⁶ kgm/s.

Explanation:

Data:

Mass = 1.5 g => 0.0015 kg

Velocity = 0.5 cm/s => 0.005 m/s

Momentum = ?

Formula:

Momentum = Mass × Velocity

P =mv

Solution:

Momentum = 0.0015 kg × 0.005 m/s

Momentum = 0.0000075 kgm/s => 7.5 × 10⁻⁶ kgm/s

The magnitude of the marble's Momentum is 7.5 × 10⁻⁶ kgm/s.

b mirrors submit a iisner? e. for which optical devices does d sometimes have a positive value? o a a and b o b. a and c o c. b and d 0 d. b and cb

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach