A train starts from rest and accelerates uniformly until it has traveled 5.6 km and acquired a velocity of What is the approximate acceleration of the train during this time?

you need add the numbers

Explanation: you need to add the numbers

0.16 m/s²

Explanation;

From one of the equation of linear motion;

vf2 - vi2 = 2ax

Where;

vf = final speed after traveling a distance x at constant acceleration; vf = 42 m/s

vi = initial speed = 0 (starts from rest)

a = constant acceleration while traveling a distance x

x = distance traveled at constant acceleration; x = 5.6 km = 5600 m

Therefore;

a = vf2/(2x)

 = 422/(2*5600) m/s²

 = 0.1575 m/s²

  ≅ 0.16 m/s²

if you already have the answer to (a), then just work out how many periods there are in 1 minute, and that's the answer to (c).

powerful computers now, not then