The free-fall acceleration at the surface of planet 1 is 10 m/s2. The radius and the mass of planet 2 are twice those of planet 1. What is the free-fall acceleration on planet 2?

d) the number of neutrons plus the number of protons

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

it's a b and