A box of mass m=10.0 kg, initially at rest, is pushed by a constant horizontal force of F=25.0 N for a distance d=10.0 m before reaching the bottom of a hill. The force stops and the box slides up the hill of height h=2.0 m. It hits a spring which compresses by an amount x=2.5 meters before the box stops. a) What is the speed of the box before it climbs up the hill?

b) What is the spring constant?

Aliquid is an answer i hope this

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.