A beam of length 5 m and mass 40 kg is placed on top of two posts: the first post is under the left end of the beam and the second post is 3 m to the right from the first post. A child with mass 20 kg starts walking along the beam from left to right. How close can he get to the right end of the beam without falling over

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

1 the 4 is sig

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft