I'll give brainlest *the first pic is for Alberto and second for the mouse*
Question 1
Alberto created a graph to illustrate his trip. Answer the questions below.
A. How does Alberto's motion change at point B?
B. What is Alberto's speed from point C to point D?
C. What happens at point D? (1 point)

Question 2
Answer the question below about Smokey The Mouse.
A. Use inertia to explain how a balanced force will affect his motion. (Newton's 1st Law)
B. What are two ways Smoky can increase his speed? (Use Newton's 2nd Law to help you)
C. What is an example of an action and reaction at work in this picture? (Use Newton's 3rd Law to help you)

The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.

At point B, Alberto's distance covered increases with time, equal distance is covered in equal time interval. The speed increases uniformly. At the point C to D, the distance covered with time remains the same. At the point D, equal distance is no longer covered in equal time intervals.

According to the law of inertia, an object will remain at rest or in a state of uniform motion unless it is acted upon by an unbalanced force. This means that smokey mouse will continue moving uniformly unless a force acts on it.

From Newton's second law; F = ma and a = F/m. F = force , m= mass, a = acceleration. This implies that smokey mouse can increase its speed by;

Increasing the force acting on the mouse

Decreasing the mass of the mouse

Action and reaction is encountered as the mouse is walking. The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.

Explanation:

vapour or gas assuming atmospheriv pressure