In a collision, a car of mass 1000kg travelling at 24m/s comes to rest in 1.2s calculate a. the change in momentum of the car
b. the steady stopping force applied to the car

a. 24,000

b. -20,000 N

Explanation:

a. p = m•v

1,000•24 = 24,000

1,000•0 = 0

∆p = 24,000

b. F = m•a

a = ∆v/∆t

a = -24/1.2

a = -20 m/s²

F = 1,000•(-20)

F = -20,000

increases it

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.