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Physics, 25.11.2021 09:30 edgar504xx

tác dụng 1 lực Fx=-(3x^2+1) để hãm vật khối lượng 2kg đang chuyển động thẳng theo trục ox tuwfd vị trí x=2 m cho đến khi dừng lại tại vị trí x=4 m . tốc đọ của vật tại vị trí x=2 m bằng .

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tác dụng 1 lực Fx=-(3x^2+1) để hãm vật khối lượng 2kg đang chuyển động thẳng theo trục ox tuwfd vị t...
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