Small spherical steel balls fired from a machine strike a circular target of area of 0.60 m2. Each ball has a velocity of +400 m/s before impact and ˗350 m/s after impact. In a given time interval of 0.30s, 300 balls strike the target on average per square meter. If each ball has a mass of 50 g, what is the magnitude of the average force exerted by the steel balls on the target?

Now that we have a feel for the state of the circuit in its steady state, let us obtain the expression for the current in the circuit as a function of time. note that we can use the loop rule (going around counterclockwise): e−vr−vl=0. note as well that vr=ir and vl=ldidt. using these equations, we can get, after some rearranging of the variables and making the subsitution x=er−i, dxx=−rldt. integrating both sides of this equation yields x=x0e−rt/l. use this last expression to obtain an expression for i(t). remember that x=er−i and that i0=i(0)=0. express your answer in terms of e, r, and l. you may or may not need all these variables. use the notation exp(x) for ex.