A projectile is shot on level ground with a horizontal velocity of 17 m/s and a vertical
velocity of 34 m/s.

-Find the time the projectile is in the air.
The acceleration due to gravity is 9.8 m/s2.
Answer in units of s.
-Find range R.
Answer in units of m.

time rising = 34 / 9.8 = 3.47 sec

total time in air = 2 * 3.47 sec = 6.94 sec

(time rising must equal time falling)

R = 17 m/s * 6.94 s = 118 m

Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

theta = 63.4 deg

2 theta = 126.9 deg

sin 126.9 = .8

v^2 = 17^2 + 34^2 = 1445 m^2/s^2

R = 1445 * .8 / 9.8 = 118 m    agreeing with answer found above

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle