A jet plane flying 600 m/s experiences an acceleration of 39.24 m/s² when pulling out of the circular section of a dive. What is the radius of curvature of this section of the dive? The options are:

1.2 km
5.8 km
0.64 km
9.2 km
7.0 km

Explanation:

If we are to assume that the plane is at the bottom of a circular movement and just about to depart in level flight, then

(39.34 - 9.81) = 600²/R

R = 12,190.992211... m

Which is very close to the 1.2 km option

the answer is d. 4

hope this

also the more points you give the faster your questions get answered

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.