A 1kg apple and a 8 kg apple falls from a height of 10m ,find the time taken by them to fall at ground if no external force acts on it except gravity. (take g=10m/s²)

An apple of 1 kg is dropped from 10.0m. How long does it take to hit the ground?

List the known and unknown quantities from the question.

u = initial velocity = 0 m/s

s = displacement = -10.0 m

g = acceleration due to gravity = -9.8 m/s²

t = time interval = ? s

Use the following kinematic equation.

s = ut + ½gt²

Since u = 0 m/s, ut = 0, and the equation can be rewritten.

s = ½gt²

Solve for t.

t² = 2s/g

t = √(2s/g)

t = √(2 × (-10.0 m))/(-9.8 m/s²)

t = √(-20.0 m)/(-9.8 m/s²) = 1.4 s

An apple of 8 kg is dropped from 10.0m. How long does it take to hit the ground?

mgh = 1/2×mv 2

wher m is the mass of the body v is velocity and g is acceleration due to gravity and h is the height

2gh=v 2

2×9.8×10 = v 2

v 2 = 196

v= 14m/s

T=v/g=1.4s

By any way you solve there is no role of mass here

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: