How far would a cantaloupe fall in 5.0 seconds of true free fall?
pliz explain

49 m

Explanation:

dude lets get one thing straight. it dont matter if this is a CANTALOUPE, a CHAIR, a BOWLING BALL, it dont matter. so remember that when you are dealing with these types of physics questions. in TRUE FREE FALL we dont care about air resistance (what is air resistance? just think about a leaf falling, or a piece of paper falling, it doesnt fall straight down but kinda goes from side to side)

ok so gravity is 9.8 meters per second squared. so all you gotta do is multiply 5.0 by 9.8!

you get 49 m

i'm thinking more like energy

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s