Suppose that a cockroach running at 0.290 m/s speeds up at a rate of 0.120 m/s/s. If the cockroach maintains this acceleration for 11.84 s, how far will he have traveled during that time period? m

10 is the . . .

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.

Gotta have a picture ^^

Amperes. i got it right on edgenuity