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Physics, 11.10.2021 06:00 phillipfruge3

Một vật có khối lượng m = 10,0 kg đang nằm yên trên mặt phẳng ngang thì chịu tác dụng của lực kéo F⃗⃗ theo phương tạo với mặt ngang một góc  = 300 như hình vẽ. Cho biết hệ số ma sát trượt giữa vật và mặt phẳng ngang là  = 0,2. Lấy gia tốc rơi tự do g = 10 m/s2 . Để vật trượt với gia tốc a = 0,50 m/s2 thì độ lớn của lực F phải bằng bao nhiêu?

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Một vật có khối lượng m = 10,0 kg đang nằm yên trên mặt phẳng ngang thì chịu tác dụng của lực kéo F⃗...
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