In terms of energy transfer, how is a rise in
temperature different from a drop in
temperatu...
Physics, 09.10.2021 03:20 chynad6395
In terms of energy transfer, how is a rise in
temperature different from a drop in
temperature?
Answers: 3
Physics, 22.06.2019 09:50
If an athlete runs once around a track, back to the starting line, her average velocity is zero. true or false?
Answers: 3
Physics, 22.06.2019 14:00
How to tell if two objects are in thermal equilibrium 1.the objects have the same temperature 2.the objects are the same size 3.the objects are touching each other 4.the objects temperatures are changing
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Physics, 22.06.2019 21:00
Which of the following statements comparing electron microscopy and light microscopy is false? which of the following statements comparing electron microscopy and light microscopy is false? both the electron microscope and the light microscope use the same wavelengths for illumination. images produced by light microscopes can be in color, whereas electron microscope images are black and white unless they are artificially colored. the electron microscope has greater resolution than the light microscope. electron microscopes can allow examination of viruses and internal cell structures, whereas light microscopes are limited to objects that are 0.5 micrometers and larger. request answer
Answers: 2
Physics, 22.06.2019 23:00
Acommon technique in analysis of scientific data is normalization. the purpose of normalizing data is to eliminate irrelevant constants that can obscure the salient features of the data. the goal of this experiment is to test the hypothesis that the flux of light decreases as the square of the distance from the source. in this case, the absolute value of the voltage measured by the photometer is irrelevant; only the relative value conveys useful information. suppose that in part 2.2.2 of the experiment, students obtain a signal value of 162 mv at a distance of 4 cm and a value of 86 mv at a distance of 5.7 cm. normalize the students' data to the value obtained at 4 cm. (divide the signal value by 162.) then calculate the theoretically expected (normalized) value at 5.7 cm.
Answers: 2
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