a 5kg-jumps on a table with a mass 30kg. as the dog walk around on top of the table what is the average force that the table applies to the dog?

Problem:

a 5 kg dog jumps on table with a mass of 30 kg what is the average force that the table applies to the dog.

Note:

What ever is the force applied by the dog to the table, it will be the same force exerted by the table to the dog but in opposite direction. Study on the Newton's Third law of motion

Given Data:

m ( mass ) = 5 kg

a ( acceleration ) = 9.8 m/s²

F ( Force ) = ? unknown

Solution:

We will use the formula of Force ( F = m × a ) in order to solve the problem.

F = m × a

= 5 kg × 9.8 m/s²

= 49 kg·m/s²

= 49 N

The table will exert 49 N of Force to the dog

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )