Calculate the binding energy per nucleon of the Boron isotope B-10 that has a nuclear mass of 10.012937 u. Remember to identify all of your data, write the equation, and show your work. (mass of proton = 1.007825 u, mass of neutron = 1.008665 u, and 1 u = 931.5 MeV

Explanation:

First, let us find the mass defect. The Beryllium nucleus contains 4 protons and 5 neutrons.

Mass of 4 protons =4×1.008=4.032u; Mass of 5 neutrons =5×1.009u=5.045u

Total mass of protons (4) and neutrons (5) =4.032+5.045=9.077u

Mass defect =9.077−9.012=0.065u

The mass defect converted into equivalent energy gives binding energy.

1u=931.5MeV

∴0.065u=0.065×931.5MeV=60.5475MeV

Binding energy per nucleon =

Numberofnucleons

Bindingenergy

=

9

60.5475

=6.7275MeV

Mark ‼️ it brainliest if it helps you ❤️

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .