A ball is launched with an initial velocity of 4.47 m/s at an angle of 66° from the horizon. a. What is the maximum height the ball attained?
b. How long did it take the ball to return to the launching height?
c. How far away did it land?

See answers below

Explanation:

a.

(vf)² = (vi)² + 2gy

0 = (4.47sin66°)² + 2(-9.8)y

y = 0.00072 m

b.

vf = vi + gt

0 = (4.47sin66°) + (-9.8)t

t = 0.012 s

0.012 x 2 = 0.024 s

c.

x = (vi)t + (1/2)at²

x = (4.47cos66°)(0.024) + 0

x = 0.107 m

an ion is a charged atom or molecule. it is charged because the number of electrons do not equal the number of protons in the atom or molecule. an atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.