blocks x and y are attached to each other by a light rope and can slide along a horizontal surface. Mass of block x is 10 kg and that of block y is 5 kg. the magnitude of force of friction on blocks x and y is 8.0 N and 4.0N respectively. Find the action-reaction forces that the blocks exert on each other if an applied force of 40 N(right) acts on block per illustration below.

Blocks x and y exerts action-reaction forces on each other with 146.1 N and 53.1 N respectively.

The given parameters:

mass of block x = 10 kg

mass of block y = 5 kg

magnitude of the frictional force of block x = 8 N

magnitude of the frictional force of block y = 4 N

the applied force to the right = 40 N

To find:

The block y pulls block x to the left with the following reaction forces;

Force of block y = force due to its own weight + frictional force

where;

g is the acceleration due to gravity = 9.81 m/s²

Thus, block y reacts on block x with a force of 53.1 N

The block x acts on block y towards the right direction with following forces;

Force of block x on y =  force due to its own weight + frictional force + applied force to the right

Thus, block x acts on block y with a force of 146.1 N

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d) physical means can be used to separate the components of air.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this