A 2.00 kg mass hangs at rest 1.50 meters above the floor. The hanging mass is attached to a spool by a massless string that runs over a frictionless pulley. The string is wrapped around a spool with a radius of 0.12 meters. The mass is released causing the spool to spin. The moment of inertia of the spool is 0.72 kgm^2. Required:
What is the linear velocity of the mass just before it hits the floor and what is the angular velocity of the spool at that moment?

the answer is b, have negligible mass

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2