Two charges of equal magnitude q1 = q2 = 6 microC are on the taxis at y = 3cm and ​

what are the statements? x

hèllo, sorry i really need some more points so if you need this qustion answered than retype it

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j