A skateboarder travels on a horizontal surface with an initial velocity of 3.6 m/s toward the south and a constant acceleration of 1.8 m/s^2 toward the east. Let the x direction be eastward and the y direction be northward, and let the skateboarder be at the origin at t=0. a. What is her x position at t=0.60s?
b. What is her y position at t=0.60s?
c. What is her x velocity component at t=0.60s?
d. What is her y velocity component at t=0.60s?

a) The x-position of the skateboarder is 0.324 meters.

b) The y-position of the skateboarder is -2.16 meters.

c) The x-velocity of the skateboard is 1.08 meters per second.

d) The y-velocity of the skateboard is -3.6 meters per second.

Explanation:

a) The x-position of the skateboarder is determined by the following expression:

(1)

Where:

- Initial x-position, in meters.

- Initial x-velocity, in meters per second.

- Time, in seconds.

- x-acceleration, in meters per second.

If we know that , , and , then the x-position of the skateboarder is:

The x-position of the skateboarder is 0.324 meters.

b) The y-position of the skateboarder is determined by the following expression:

(2)

Where:

- Initial y-position, in meters.

- Initial y-velocity, in meters per second.

- Time, in seconds.

- y-acceleration, in meters per second.

If we know that , , and , then the x-position of the skateboarder is:

The y-position of the skateboarder is -2.16 meters.

c) The x-velocity of the skateboarder (), in meters per second, is calculated by this kinematic formula:

(3)

If we know that , and , then the x-velocity of the skateboarder is:

The x-velocity of the skateboard is 1.08 meters per second.

d) As the skateboarder has a constant y-velocity, then we have the following

The y-velocity of the skateboard is -3.6 meters per second.

what is the actual question though?