When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy is absorbed by the ethyl alcohol? (Assume the density of ethyl alcohol to be 0.790 g/mL.)

Q = 194.34  J

Explanation:

Given that,

100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.

We need to find the amount of thermal energy  absorbed by the ethyl alcohol.

The density of ethyl alcohol is 0.790 g/mL.

The formula for heat absorbed is given by :

So, 194.34  J of thermal energy is absorbed by the ethyl alcohol.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.