A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror? • -5.0 cm
• 7.5 cm
• -7.5 cm
• 5.0 cm

5.0cm

Explanation:

To get the height of the image, we will use the magnification formula as shown:

m = Hi/H = v/u

Hi is the image height

H is the object height

v is the image distance

u is the object distance

First, we need to get the image distance v

Using the mirror formula;

1/f = 1/v+ 1/u

1/-6 = 1/v + 1/12

1/v = -1/12 - 1/6

1/v = -1-2/12

1/v = -3/12

v = 12/-3cm

v = -4cm

Next is to get the image height Hi

Using the expression;

Hi/H = v/u

Hi/15 = 4/12

Hi/15 = 1/3

3Hi = 15

Hi = 15/3

Hi = 5.0cm

Hence the image height is 5.0cm

true is the correct answer

hope i

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.