Please answer me my question A cylindrical container with a radius of cross section 70 cm is filled with 200 litres of water . find the pressure exerted by the water at the bottom of the container.( Take g=10 m/s^2)​

1299 N/m²

Explanation:

Applying,

P = ρgh Equation 1

Where P = pressure of water at the bottom of the container, ρ = density of water, h = height of water in the container, g = acceleration due to gravity.

but,

V = πr²h Equation 2

Where V = volume of water, r = radius of the container

make h the subject of the equation

h = V/πr² Equation 3

From the question,

Given: V = 200 liters, = 200000 cm³, r = 70 cm

Constant: π = 22/7

Substitute these values into equation 3

h = 200000/[(22/7)(70²)]

h = 12.99 cm

h = 0.1299 m

Also given

Constant: g = 10 m/s², ρ = 1000 kg/m³

Substitute these values into equation 1

P = 0.1299(10)(1000)

p = 1299 N/m²

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