An archer shoots an arrow horizontally at a target 11 m away. the arrow is aimed directly at the center of the target, but it hits 56 cm lower. What was the initial speed of the arrow?

Explanation:

Given :

Distance in the vertical  direction, S = 56 cm

                                                               = 0.56 m

Initial velocity in the vertical direction, u = 0 m/s

Acceleration due to gravity, g = 9.81

Therefore, in order to find the time required,

t = 0.33 seconds

Therefore, the initial velocity of the arrow is given by :

     , where S = 11 m and t = 0.33 seconds

Thus the initial velocity of the arrow is 33.33 m/s.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards