An artificial satellite circling the Earth completes each orbit in 125 minutes. (a) Find the altitude of the satellite.(b) What is the value of g at the location of this satellite?

(a) Altitude = 1.95 x 10⁶ m = 1950 km

(b) g = 5.9 m/s²

Explanation:

(a)

The time period of the satellite is given by the following formula:

where,

T = Time period = (125 min)() = 7500 s

r = distance of satellite from the center of earth = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

= Mass of Earth = 6 x 10²⁴ kg

Therefore,

r = 8.29 x 10⁶ m

Hence, the altitude of the satellite will be:

Altitude = 1.95 x 10⁶ m = 1950 km

(b)

The weight of the satellite will be equal to the gravitational force between satellite and Earth:

g = 5.9 m/s²

atomic = no of protons.

mass number-atomic number = neutron number