Two objects with masses of 2.75 kg and 4.45 kg are connected by a light string that passes over a light frictionless pulley to form an Atwood machine. Required:
a. Determine the tension in the string.
b. Determine the acceleration of each object.
c. Determine the distance each object will move in the first second of motion if they start from rest.

Explanation:

F = ma

4.45g - 2.75g = (4.45 + 2.75)a

a = 9.81(4.45 - 2.75) / (4.45 + 2.75) = 2.31625 ≈ 2.32 m/s²

a)

T = 2.75(9.81 + 2.32) = 33.3 N

or

T = 4.45(9.81 - 2.32) = 33.3 N

b) 2.32 m/s² upward for 2.75 kg mass

    2.32 m/s² downward for 4.45 kg mass

c) y = ½at² = ½(2.31625/3)1² = 1.158125 ≈ 1.16 m

d. learned preferences i believe is your answer

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation: