A horizontal pipe with water flowing through it has a circular cross section that varies in diameter. the diameter at the wide section is 4 times the diameter at the narrow section. If the rate of flow of the water in the narrow section is 9.0 L/min, the rate of flow of the water in the wide section is:

9.0 L/min

Explanation:

From the given information, the flow rate in the wider section appears to four times that of the narrow section.

Since the flow rate for a pipe at any time (t) = Area (A) × speed (V)

we can say that:

Then, the flow rate in the wider section will also be 9.0 L/min. This is because the mass flow rate must be kept constant regardless of the changes in the size of the cross-sectional area.

answer; i believe the correct answer is (40,000 j) good luck

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.