Three 15-Ω and two 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes through each bulb? 1) 0.18 A
2) 0.25 A
3) 0.51 A
4) 0.74 A
5) The current will be 1.6 A in the 15-Ω bulbs and 0.96 A in the 25-Ω bulbs.

I = 0.25 A

Explanation:

Given that,

Three 15 ohms and two 25 ohms light bulbs and a 24 V battery are connected in a series circuit.

In series combination, the equivalent resistance is given by :

So,

The current each resistor remains the same in series combination. It can be calculated using Ohm's law i.e.

V = IR

So, the current of 0.25 A passes through each bulb.

i think if it were me i whould divide 300 dide 15

step-by-step explanation: