A stone is thrown vertically upward with an initial velocity of 40m/s. Taking g = 10 m/s^2 find the maximum height reach by the stone and what is the net displacement and distance covered by the stone.​

The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.

Explanation:

Final velocity v = 0

Initial velocity u = 40m/s

We know that,

Using equation of motion

× ×

The maximum height is:

The  stone will reach at the top and will come down

Therefore, the total distance will be:

The net displacement is:

Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.

hope this helps.....

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