A 1540-kg truck has a wheel base of 3.13 m (this is the distance between the front and rear axles). The center of mass of the truck is 1.09 m behind the front axle. a) What is the force exerted by the ground on each of the front wheels?b) What is the force exerted by the ground on each of the back wheels? Hint: Remember that the truck has four wheels.

Explanation:

Sum moments about the rear tires to zero to find the force on the front tires

F[3.13] - 1540(9.81)[3.13 - 1.09] = 0

F = 9,846

so each front wheel supports half of that weight

F/2 = 9846/2 = 4,923 ≈ 4920 N

Sum vertical forces to zero

9,846 + R - 1540(9.81) = 0

R = 5,261

so each rear wheel supports half of that weight

R/2 = 5261/2 = 2630.52 ≈ 2630 N

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

your answer is, orbit around the nucleus