A 84-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.73 as. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.4 s, and then comes to rest. What does the spring scale register During the first 0.80s of the elevator’s ascent?

Explanation:

From the question we are told that:

Mass

Speed

Acceleration Time

Constant speed Time

Deceleration time

Generally the equation for Acceleration is mathematically given by

Therefore acceleration for the first 0.80 sec is

Therefore

Spring Reading=Normal force -Reaction

3.2x10^7

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