Suppose that 2 J of work is needed to stretch a spring from its natural length of 32 cm to a length of 46 cm. (a) How much work (in J) is needed to stretch the spring from 37 cm to 41 cm

the work required is 0.163 J

Explanation:

Given;

Energy applied to the spring, E = 2 J

initial length of the spring, x₀ = 32 cm

final length of the spring, x₁ = 46 cm

Extension of the spring, Δx = x₁ - x₀ = 46 cm - 32 cm = 14 cm = 0.14 m

The spring constant is calculated as follows;

E = ¹/₂kΔx²

The extension of the spring when it is stretched from 37 cm + 41 cm:

Δx =  41 cm - 37 cm = 4 cm = 0.04 m

The work required:

W = ¹/₂kΔx²

W = ¹/₂ x (204.1) x (0.04)²

W = 0.163 J

Therefore, the work required is 0.163 J

1 a

2 b

3 b

4 d

5 d

6 d

explanation:

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia