A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the other tower. He notes that it takes 0.9 s for the wave to travel the 26 m to the opposite tower. If one meter of the rope has a mass of 0.28 kg, find the tension in the tightrope.

the tension in the tightrope is 233.68 N

Explanation:

Given the data in the question;

Time taken to reach the opposite tower t = 0.9 s

Distance between the two towers S = 26 m

mass per one meter length =  0.28 kg

First we calculate the velocity;

Velocity V = Distance / time

we substitute

Velocity V = 26 m / 0.9 s

Velocity V = 28.889 m/s

We know that Velocity V can also be expressed as;

V = √( T / m )

we make T the subject of formula

V² = T / m

T = mV²

we substitute

T = 0.28 × ( 28.889 )²

T = 233.68 N

Therefore,  the tension in the tightrope is 233.68 N

atomic = no of protons.

mass number-atomic number = neutron number

where are the vectors ?