Two blocks A and B with mA = 2.9 kg and mB = 0.87 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6 N. Determine the tension in the string connecting the two blocks.

Tension = 1.38 N

Explanation:

Given that:

Mass of block A = 2.9 kg

mass of block B = 0.87 kg

Force F = 6 N

Assume a = acceleration of the blocks.

Then:

(a) + (a) = 6

2.9a + 0.87a = 6

3.77a = 6

a = 6/3.77

a = 1.59 m/s²

Suppose T to be the tension in the string.

If we take a look at the forces acting on the first block, then:

F - T = (a)

T = F - (a)

T = 6 - 2.9(1.59)

T = 6 - 4.62

T = 1.38 N

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

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