Physics, 17.06.2021 02:50 marahsenno

g A car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration

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Answer from: cece4874

8761.5 N

Explanation: Given that a car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration

Mass m = 1120kg

First change km/h to m/s

(80 × 1000) ÷ 3600

Velocity = 22.2 m/s

Acceleration = ( 22.2 - 0 ) ÷ 10

Acceleration = 2.2 m/s^2

Force F1 = mass × acceleration

Substitutes all the parameters into the formula

F1 = 1120 × 2.2

F1 = 2489 N

For the car to come to rest, it will be decelerating.

Using 3rd law of motion

V^2 = U^2 + 2as

V = 0 since it is coming to rest.

Substitute all the parameters into the formula

0 = 22.2^2 - 2 × a × 44

88a = 492.84

a = 492.84/88

a = 5.6 m/s^2

The force F2 = 1120 × 5.6

F2 = 6272.5N

Net force = 6272.5 + 2489

Net force = 8761.5 N

Therefore, the net force is 8761.5 N

Answer from: Quest

explanation:

because they are cartillidge

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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g A car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the...

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