A ball of mass 100g thrown by a man moves at a velocity of 100m/s. what is the momentum? need the answer step by step pl!!​

Explanation:

Mass of the ball= 100 g = 0.1 kg

Velocity of the ball before collision=10 m/s

Momentum of the ball before collision, p(i)=mv= 0.1×10=1 kgm/s

Since, ball returns back with same velocity

Therefore, velocity of ball after collision = -10 m/s (-ve sign due to opposite direction)

So, momentum of ball after collision,p(f) = 0.1 ×(-10) = -1 kgm/s

Now, Impulse generated in the ball= change in momentum= p(f)-p(i)= -1–1= -2 kgm/s

b would be the answer

6/12=1/2

step-by-step explanation: