A bug flies east at 2.5 m/s. A light breeze blows on the bug with a velocity of 2.5 m/s due east. What is the resultant velocity of the bug?

5 m/s

Explanation: Given that a bug flies east at 2.5 m/s. A light breeze blows on the bug with a velocity of 2.5 m/s due east. What is the resultant velocity of the bug?

Since the bug flies due east with a velocity of 2.5 m/s, in the same direction to the blowing breeze, which is of 2.5 m/s, the resultant velocity will be the addition of the two velocities. That is

Vr = Vb + VW

Where

Vr = resultant velocity

Vb = velocity of the bug = 2.5 m/s

VW = velocity of the breeze. = 2.5 m/s

Vr = 2.5 + 2.5

Vr = 5m/s

Therefore, the resultant velocity is 5m/s

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this