The diagram represents alpha particle A approaching a gold nucleus. D is the distance between the path of the alpha particle and the path for a head-on collision. head-on colision
gold nucleus
If Dis decreased, the angle of deflection () of the alpha particle would
1.
decrease
2
increase
remain the same

This is what i found on google “kinetic energy. energy is transferred from one object to another when a reaction takes place. energy comes in many forms and can be transferred from one object to another as heat, light, or motion, to name a few. this energy would be in the form of motion, with the person lifting the blue ball to a higher level.” i hope this you

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Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge