The center-to-center distance between a 200-g lead sphere and an 800-g lead sphere is 0.120 m. A 1.00-g object is placed 0.0800 m from the center of the 800-g sphere along the line joining the centers of the two spheres. (a) Ignoring all sources of gravitational force except the two spheres, calculate the gravitational force exerted on the object.
(b) Determine the gravitational potential energy per gram at the position of the object.
(c) How much work is needed to bring the object 0.0400 m closer to the 800-g sphere?

with 5 seconds, no, but over time if the police car stays at 65m/s ad the speeding car stays at 60, then obviously yes, but the answer to your question would be, no.

hope this : )

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

i believe the answer is a hope it and is correct