A 9.0 V potential difference is applied between the ends of a 0.70-mm-diameter, 65-cm-long nichrome wire. What is the current in the wire?

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.