two particles woth each charge magnitude 2.0×10^-7 c but opposite signs are held 15cm apart. what are the magnitude and direction of the electric field E at tge point midway between charges​

The magnitude of the electric field strength is 6.4 x 10⁵ N/C, directed from positive particle to negative particle.

Explanation:

Given;

charge of each particle, Q = 2 x 10⁻⁷ C

distance between the two charges, r = 15 cm = 0.15 m

distance midway between the charges = 0.075 m

The magnitude of the electric field is calculated as;

The direction of the electric field is from positive particle to negative particle.