a ball is projected horizontally with a velocity of 5 m per second from the top of a building 19.6 m high how long will the ball take to hit the ground(g=10m/s2)​

1.98s

Explanation:

The time taken to hit the ground is given by

h=ut+ 1/2 at^2

but u =0

so we have

h=1/2at^2

making t the subject

t=√2h/g

√2×19.6/10

1.98s

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation:

they should be similar or the same